You have approximately 34 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 7.5 feet? (total displacement is 638 tons)

Correct Answer: Option C — 0.4 foot

Applying the formula $\Delta KG = (w \times d) / W$, multiplying 34 tons by the 7.5-foot distance and dividing by the 638 tons total displacement results in a calculated shift of approximately 0.4 foot.