While steaming at 18.9 knots, your vessel consumes 386 barrels of fuel oil per day. In order to reduce consumption to 251 barrels of fuel oil per day, what is the maximum speed the vessel can turn for?

Correct Answer: Option A — 16.4 knots

Apply the fuel consumption law: (S1/S2)^3 = F1/F2. Given 18.9 knots at 386 barrels, the ratio of fuel reduction to 251 barrels requires a speed reduction. Solving for S2 = 18.9 * cube root of (251/386) results in a maximum speed of approximately 16.4 knots.