What will be the resulting current when a voltage of 442.7 VDC is applied to a resistance of 1.25 ohms in figure "A" of the illustrated circuit when the switch is closed? Illustration EL-0018

Correct Answer: Option D — 354.16 amps

Dividing the applied DC voltage of 442.7 volts by the low resistance of 1.25 ohms using Ohm's law ($I = \frac{V}{R}$) yields 354.16 amperes. This calculation is vital for evaluating heavy-duty marine electrical loads and fault currents under IEEE 45 standards.